Topic: Three Indian squaws (Read 853 times)

BigR55 · « **on:** April 28, 2008, 03:04:15 PM »

There were three Indian squaws having children at the same time.

The first squaw slept on a bear hide and she had a son.

The second squaw slept on a deer hide and she had a son.

The third squaw slept on a hippopotamus hide and she had twin sons.

So.........what do you think this means?

ready?

scroll down....

some more....

The sons of the squaw of the hippopotamus is equal to the sum of the squaws of the other two hides!

BigR55 · « **Reply #1 on:** April 28, 2008, 03:50:08 PM »

Mathematical interpertations will be provided for a small charge!

AXIL · « **Reply #2 on:** May 05, 2008, 08:19:14 AM »

this new math gets me every time

BigR55 · « **Reply #3 on:** May 05, 2008, 11:03:29 AM »

OK, here is the explanation.

Right triangle with side A having a length of one.
The other side B having a length of one.
The third side C or the hypotenuse having a length of
1 squared + 1 squared = square root of 2
so one son squared + one son squared = square root of 2 sons

EZRIDN · « **Reply #4 on:** May 06, 2008, 10:31:17 PM »

...and don't forget the one buck meandering between three teepees.

Author Topic: Three Indian squaws (Read 853 times)

BigR55

Three Indian squaws

BigR55

Re: Three Indian squaws

AXIL

Re: Three Indian squaws

BigR55

Re: Three Indian squaws

EZRIDN

Re: Three Indian squaws