I've poured over the schematic on the locks, but there's one item that isn't sinking in, and that's the, I'll call it switching diode, between the two leads. I assume they flip-flop the polarity to fire the latches to and fro, but I'm not getting how that little bugger does it.
Can someone give me a lesson on how that little gizmo works?
Thanks
Chief
I'd not seen that on any of the parts lists I'd read so far. In fact I was assuming that the lock system fed three wired to each lock assembly (lock open/lock closed/ground). If what you're describing seeing is a bi-directional diode then there would only be two wires to each lock assembly and the relays would have a diode in them as well (can't tell that from any of the pages I've looked at).
That would make the system a little more complicated, but not terribly so. Would mean that you couldn't share a common ground with any other ground lead that goes in the bags for lights. Instead you'd have to use a ground that is isolated on the saddlebag side of the relay pack because it and the power lead would switch polarity to work the lock motor.
That's actually a more complicated setup then I'd assumed they'd used. If the switch was robust enough to handle the load and the motors had separate open and close inputs the whole system could have been done without even using relays. Even using a pair of relays to allow a light duty micro switch would have been simple though. Seems like a lot of effort to save pulling one more wire front to rear.
Don't know how long before the lock assemblies get here. When they do I'll look closely to see if there are alternative ways to trigger the motors. Will decide then the easiest way to proceed. Still doesn't sound like a big deal one way or the other.